b^3-5b^2=36b

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Solution for b^3-5b^2=36b equation:


Simplifying
b3 + -5b2 = 36b

Reorder the terms:
-5b2 + b3 = 36b

Solving
-5b2 + b3 = 36b

Solving for variable 'b'.

Reorder the terms:
-36b + -5b2 + b3 = 36b + -36b

Combine like terms: 36b + -36b = 0
-36b + -5b2 + b3 = 0

Factor out the Greatest Common Factor (GCF), 'b'.
b(-36 + -5b + b2) = 0

Factor a trinomial.
b((-4 + -1b)(9 + -1b)) = 0

Subproblem 1

Set the factor 'b' equal to zero and attempt to solve: Simplifying b = 0 Solving b = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b = 0

Subproblem 2

Set the factor '(-4 + -1b)' equal to zero and attempt to solve: Simplifying -4 + -1b = 0 Solving -4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1b = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1b = 0 + 4 -1b = 0 + 4 Combine like terms: 0 + 4 = 4 -1b = 4 Divide each side by '-1'. b = -4 Simplifying b = -4

Subproblem 3

Set the factor '(9 + -1b)' equal to zero and attempt to solve: Simplifying 9 + -1b = 0 Solving 9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1b = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1b = 0 + -9 -1b = 0 + -9 Combine like terms: 0 + -9 = -9 -1b = -9 Divide each side by '-1'. b = 9 Simplifying b = 9

Solution

b = {0, -4, 9}

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